When an AGV or AMR drive system is being selected, two questions have to be answered separately:how much load is carried by each wheel, andhow much force the driven wheels must transmit to the floor.
They are related, but they are not interchangeable. A drive module can have enough mechanical load capacity and still be unsuitable if the required wheel torque is too high, the driven wheels carry too little vertical load, or the duty cycle exceeds the continuous capability of the motor and gearbox.
For preliminary sizing, it is more useful to separate wheel load, tractive-force demand andavailable wheel-to-floor traction, then check them together at vehicle level. The calculations below are intended for engineering screening. Final values should be confirmed from the actual chassis, wheel, floor and operating cycle.
Rated load is the mechanical load that a drive unit, wheel or caster is designed to carry under its specified conditions. It does not tell you how much longitudinal force that wheel can generate at the floor.
Actual wheel load is the vertical reaction carried by a particular wheel on the finished vehicle. It depends on the centre of gravity, payload position, battery location, lifting mechanism, support-wheel arrangement, chassis stiffness, suspension or floating mountings, manufacturing tolerances and floor flatness.
Tractive force is the longitudinal force transmitted by the driven wheels to move the vehicle. It is used to overcome acceleration, rolling resistance, gradient resistance and other resistance that is actually present in the operating condition being checked.
This is why a drive module should not be selected from vehicle weight or product load capacity alone.
Use the maximum operating mass of the complete vehicle:
Vehicle self-weight should include the chassis, batteries, drive system, lifting mechanism, electrical equipment and other hardware that remains on the AGV or AMR during operation.
Convert mass to weight force when required:
where W is vehicle weight in newtons, m is vehicle mass in kilograms, andg is gravitational acceleration, approximately 9.81 m/s².
For a vehicle with clearly defined front and rear support lines, the initial reactions can be estimated from force and moment equilibrium.
Let:
This check is useful because front and rear support lines can carry very different loads. A battery pack, lifting mechanism or payload that is offset from the geometric centre can move a significant portion of the reaction force to one end of the chassis.
Front and rear reactions can be estimated from overall equilibrium, but the exact load at each corner of a rigid four-point chassis cannot always be determined from a simple planar calculation.
Actual corner reactions can also be affected by:
If individual wheel load is important for traction, bearing life or structural verification, use the actual suspension model, structural analysis or wheel-load measurement rather than presenting an equal-share calculation as the final result.
Wheel reactions change when the vehicle starts moving. Acceleration and braking transfer load longitudinally. A lifting mechanism can move the centre of gravity. Floor joints and thresholds can temporarily increase the load on one support point.
A simplified estimate of longitudinal load transfer is:
where a is longitudinal acceleration, h is centre-of-gravity height, and L is wheelbase.
In practice, two operating values matter especially during early drivetrain review:the lowest driven-wheel load, because it limits available traction, andthe highest support-wheel load, because it governs mechanical loading.
There is rarely one useful “total resistance” value that represents every AGV or AMR manoeuvre. Define the operating cases that the vehicle actually has to perform, then calculate them separately.
Do not automatically add the worst value from every case and call it the continuous requirement unless the vehicle genuinely performs those conditions at the same time.
Maximum vehicle speed alone does not determine acceleration force. Two vehicles with the same top speed can require very different peak torque if their acceleration times are different.
The rolling-resistance coefficient should not be treated as a universal material constant. Wheel diameter, tread construction, hardness, resilience, bearing type, wheel load, floor surface, temperature and speed can all influence the actual resistance.
For a real project, use validated wheel-and-floor data or vehicle measurement where possible. A preliminary coefficient can be useful for concept sizing, but it should not become a guaranteed vehicle parameter simply because it appeared in an early spreadsheet.
If the route is level, the gradient term is zero. If the route includes a ramp, calculate that ramp as its own operating case.
Caster swivel, skid steering, tyre scrub, bearings, seals, scrapers, cable chains and auxiliary mechanisms can create additional resistance. These effects are difficult to reduce to one reliable generic coefficient for every vehicle.
On a prototype or existing vehicle, push-force measurement, motor-current logging and testing at representative payload and floor conditions are often more useful than adding an arbitrary “turning resistance factor”.
Once the required vehicle-level tractive force has been established for an operating case, determine how that force is shared by the driven wheels.
For a symmetric two-wheel drive, equal force sharing can be used as a preliminary estimate:
Wheel-side torque is then:
Use the effective rolling radius where accuracy matters. A compliant tread can produce a loaded rolling radius that differs from the nominal catalogue radius.
For preliminary motor-shaft checking:
where i is gearbox ratio and η is total mechanical drivetrain efficiency. Final motor selection still requires the torque-speed profile, acceleration requirement, gearbox rating and thermal duty.
Calculated motor torque is not automatically usable traction. The approximate adhesion limit at a driven wheel is:
where μ is the available wheel-to-floor adhesion coefficient and Ndrive is the vertical load on that driven wheel.
A useful reverse check is:
This lets the engineer compare the required adhesion with the actual tread and floor condition instead of inserting one generic friction value into every project.
If one driven wheel carries less vertical load than the other, check the lower-loaded wheel individually. A larger motor does not solve a traction-limited chassis; it may only make the wheel reach slip sooner.
Starting, acceleration and some manoeuvres create short-duration peak demand. Long travel cycles and frequent turning create a different problem: heat.
Review at least:
A single “maximum power” number cannot describe the complete duty profile.
The following numbers are used only to show the calculation sequence. They are not JY Robot design recommendations and should not be copied into another vehicle project.
| Input | Example value |
| Fully loaded vehicle mass | 1,800 kg |
| Wheelbase | 1.6 m |
| CG position from rear support line | 0.9 m |
| Driven wheels | 2, on the front support line |
| Required acceleration | 0.4 m/s² |
| Effective drive-wheel radius | 0.10 m |
| Route condition | Level indoor floor |
| Steady rolling resistance used for this example | 360 N |
W = 1,800 × 9.81 = 17,658 N
Rfront = 17,658 × 0.9 / 1.6 ≈ 9,933 N
Rrear ≈ 7,725 N
The two front driven wheels therefore carry about 9.93 kN in this preliminary static model. Their individual loads still need to be verified from the actual chassis arrangement or measurement.
Facc = 1,800 × 0.4 = 720 N
Fstraight = Froll + Facc
Fstraight = 360 + 720 = 1,080 N
No gradient term is included because this example assumes a level route. If the real vehicle has a ramp, calculate that condition separately.
Fwheel ≈ 1,080 / 2 = 540 N
Twheel = 540 × 0.10 = 54 N·m per drive wheel
This is the wheel-side torque for this straight-line acceleration case before any project-specific allowance. It is not yet a final motor selection.
If the front support-line reaction were shared equally, each driven wheel would carry approximately:
9,933 / 2 ≈ 4,967 N
The minimum adhesion coefficient required to transmit 540 N would then be:
μrequired = 540 / 4,967 ≈ 0.11
The equal split is only a screening assumption. Final traction validation should use the actual lower-loaded drive wheel and verified wheel-to-floor performance. The purpose of the example is to show what needs to be checked next, not to prove that a particular motor or drive module will work from a few assumed inputs.
For an AGV or AMR drivetrain review, the most useful application data are:
The calculation is used to narrow the drivetrain options. Final selection should be checked on the actual vehicle through wheel-load measurement, representative floor testing, current and temperature monitoring, and prototype operation at the required payload and duty cycle.
Can AGV/AMR wheel load be calculated by dividing vehicle mass by the number of wheels?
Only as a rough first estimate when the centre of gravity and support geometry are highly symmetrical. Real wheel loads can differ because of payload position, chassis stiffness, suspension, mounting tolerances and floor flatness.
Is rated load capacity the same as tractive force?
No. Rated load capacity describes mechanical support capability. Tractive force describes the longitudinal force transmitted to the floor. Both have to be checked during drive-module selection.
How should rolling resistance be selected?
Use validated wheel-and-floor data or vehicle measurements wherever possible. Generic coefficients are acceptable for preliminary screening, but they should not automatically be used as final project values.
Why can a drive wheel slip even when the motor has enough torque?
The wheel can transmit only the traction allowed by its vertical load and the wheel-to-floor contact condition. If driven-wheel load is too low, additional motor torque may increase slip rather than usable force.
Should ramp, acceleration and pivot-turn resistance always be added together?
No. Define the real operating cases first. Level acceleration, ramp travel and pivot turning may represent different drivetrain conditions and should normally be checked separately unless the vehicle is genuinely required to perform them simultaneously.
Is this calculation enough for final motor selection?
No. Final motor and gearbox selection also requires continuous and peak torque, speed, acceleration, efficiency, thermal duty, control limits and vehicle-level validation.
Heavy-Duty AGV/AMR Differential Drive Module (1–8 Ton)
Product configurations for heavy-duty differential-drive AGV and AMR platforms.
How to Size a Differential Drive Module for a 6–8 Ton AGV
A vehicle-level sizing workflow for heavy-duty differential-drive applications.
Differential Drive vs Drive-Steering Units: Which Chassis Architecture Fits Your AMR?
AGV/AMR Drive-Steering Unit Selection Guide: 9 Engineering Inputs
Send the vehicle mass, chassis layout, driven-wheel arrangement, speed, acceleration, wheel information, floor condition and operating cycle. JY Robot can use these inputs for preliminary drivetrain and application review.
